0=-3g^2-72g

Solution for 0=-3g^2-72g equation:

0=-3g^2-72g

We move all terms to the left:

0-(-3g^2-72g)=0

We add all the numbers together, and all the variables

-(-3g^2-72g)=0

We get rid of parentheses

3g^2+72g=0

a = 3; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·3·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*3}=\frac{-144}{6}
=-24
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*3}=\frac{0}{6}
=0
$